Physics Practice Test – Fundamentals of Motion (Motion Under Gravity – Questions with Answers and Explanations)

A particle is projected vertically upwards with a speed of 40 ms^-1. At what times will it be 35 m above its point of projections? [Take g = 10 ms^-2]

A. 1 sec. and 7 sec.
B. 1 sec. and 8 sec.
C. 2 sec. and 5 sec.
D. 2 sec. and 7 sec.

A particle is projected vertically upward from the ground with speed 30 ms^-1. Calculate the maximum height reached by the particle. [Take g = 10ms^-2] (WASSCE 2016 FM)

A. 20 m
B. 10 m
C. 30 m
D. 45 m

An object is projected vertically upwards. Its height, h(m), at time t seconds is given by h = 20t –  t² -  t³. 

Find correct to two decimal places, the maximum height reached by the object.